﻿﻿ MatPlus.Net

Website founded by
Milan Velimirović
in 2006

21:18 UTC
 ISC 2024

Remember me

 CHESS SOLVINGTournamentsRating lists1-Jul-2024
 B P C F

MatPlus.Net Forum General Construct the longest ser-x with a Black homebase

Page: [Previous] [Next] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

I agree with Seetharaman — who would have thought that this turns out to be so attractive…
Anyhow, here is an improved version of my above try, are the additional cookstoppers sufficient??

(= 11+16 )

ser-hs=19 C?

Solution: 1.cxd6 2.Sxa6 3.Sxc5 4.a5 5.a4 6.a3 7.Ra4 8.Qa5 9.Kd8 10.Kc7 11.Kb6 12.Kb5 13.Kxb4 14.b5 15.Sxe4 16.Sxg3 17.Sxe2 18.Sxc1 19.Sxb3 & 1.c3+ Kxc3=

EDIT. Still cooked by I.e. 1.cxd6 2.dxc5 3.cxb4 4.e5 5.h5 6.h4 7.hxg3 8.Rh4 9.Rxe4 10.Rc4 11.Rxc2 12.Rxc1 13.Ke7 14.bxa6 15.Kf6 16.Kf5 17.f6 & 1.e4+ K~=
This needs more thought…

This may help inspire.

ser-hs=17 Schema
(= 10+16 )

1. cxd6 2. Qxb6 3. Qxg1 8. bxa1=Q 9. Qxa6 10. Qd3 15. a1=Q 16. Qe5 17. Ra1 & 1. h4 h5

The move h3-h4 doesn't force a selfstalemate.
A queen on h3 could play Qh3xd7+ Kxd7=

Another question:
Is wPa4 in Ser-hs=16 (197) necessary? The solution works without it
and I see no other way for the rook walk.

Instead of Qe5 Ra1, black can also play Ra5 Re5, or a1=S Sc2 Ra1. And the latter cook means that perhaps moving Olaf's queen to e2 may fix this.
(= 10+16 )

1. cxd6 2. Qxb6 3. Qxg1 8. bxa1=Q 9. Qxa6 10. Qd3 15. a1=S 16. Sxc2 17. Ra1 & 1. Qxe7 K/B/Sxe7=

This is cooked i.e. by 1.cxd6 2.Qxb6 4.Qd3 9.bxa1=B 11.Bxc1 12.Bxd2 13.h5 16.Rxg1 & 1.Qxe7+
And with an additional wPc2 also 1.cxd6 2.Qxb6 4.Qd3 9.bxa1=R 10.Sc6 12.Sxc2 13.h5 16.Rxg1 & 1.Qxe7+

More trying is the only way forward.

ser-hs=18 Schema

(= 11+16 )

1. cxd6 2. Qxb6 3. Qxb4 4. b5 5. bxa4 8. a1=Q 9. Qaxa5 10. Qxg5 15. a1=Q 16. Qb2 17. Ra1 18. Ba6 & 1. Qxd7 K/N=

@446
Cooked

1.cd-Qb6-Qxb4-Qxa4-5.Qxa5-Qxg5-Qg1-a5-a4-10.a3-a2-a1R-Ra3-Rxc3-15.Rxe3-16.Ra2 & Qxd7+

Posted by Алексей Гаспарян

I offer a new position.

(= 9+16 )

Ser-hs#14
Solution: 1.cd 2.ab 3.ba 4.a4 5.ab 6.Ra4 7.Qa5 8.Kd8 9.Kc7 10.Kc6 11.Kd5 12.Ke4 13.Kf3 14.Re4 Ne1+ 15.Q(R)*e1X.

Dear chess friends!
Do you think this could work?

Cooked in 13 moves:
1. exd6 2. d5 3. c5 4. c4 5. cxd3 6. g6 7. gxf5 8. Qf6 9. Ba3 10. Kf8 11. Kg7 12. Bc1 13. Qa1 Be7+ Bg5#

I suggest adding a white pawn g4.

Cooked in 13 moves:
1. exd6 2. c5 3. c4 4. cxd3 5. Qxg5 6. Ke7 7. Kf6 8. Ke5 9. Kd4 10. Kc3 11. Qe3 12. d5 13. d4 - Rc2+ dxc2#

Olaf,most likely,this scheme does not allow to do it in 14 moves,but it might be possible to do it at least in 13, if you force 1.cd
I would like to know this in this position:
W: Kd1,Re6,Rg2,Bg5,Nd3,Nd6,pp.b3,e5,g4 (9) B: homebase (16) Ser.hs#13 C?
Thank you!

1.cxd6 2.Qa5 3.Qxe5 4.Qxg5 5.Qe5 6.Qc3 7.Kd8 8.Kc7 9.Kc6 10.Kd5 11.Kd4 12.Kxd3 & Rd2+ Qxd2#

Thank you,Arno!When you're working on a plan,it's hard to find a cook. I modified the diagram a little.Now to get to f3 the king needs to destroy the c6 bishop. Can this help you survive? Please also look at this attempts of mine.
W: Kd1,Rb6,Bc6,Bg3,Nd3,Nd6,pp.a5,b3,e6,f2,h3 (11) B: homebase (16) Ser.hs#14 C?
or without rook b6 and pawn a5 - Ser.hs#13 C?

1.exd6 2.dxc6 3.Ke7 4.Kxe6 5.Kd5 6.Ke4 7.Kf3 8.Qf6 9.Qc3 10.Bf5 11.Be4 12.d5 13.Bb4 & Se1+ Qxe1#

How not to let the black king go along a different route - apparently this requires even deeper thought.
Arno, by the way, I recently tried to correct your ser.h=19 (see posts 397,403)
W:Kf2,Qb5,Re2,Bh2,Bh5,Ne1,Ne3,pp.b6,c4,e6,f5,g3,h6 (13)
B:homebase (16) Ser.h=19 with solution : 1.ab 2.Ra4 3.R*c4 4.Rc6 5.d5 6.d4 7.d3 8.de 9.Qd2 10.Nd7 11.Rc3 12.R*e3 13.R*g3 14.Q*h6 15.Qg6 16.h6 17.Qh7 18.Rg6 19.f6 B*c7=.
Could this work?

OK, who else is yearning for an AI which not only finds cooks, but
tries edits to fix them? :-)

With not so many attempts, new records should be possible in the ser-hs field.
Should not (197) be Tüngler/Mladenovic in view of (195)?

(= 8+16 )
ser-hs#16 C?

(460) Posted by Arno Tungler [Sunday, Feb 18, 2024 02:36]

There were quite some attempts 200 posts ago...
I fully agree with the [197] - it is MM & AT but I am also 100 % sure that this is not the last word...
For Michel's ser-hs#16 it would be good to have the solution.