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MatPlus.Net  Forum Moremovers Mate in 2, 5 & 6 moves |
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| | | (1) Posted by Roddy McKay [Wednesday, Apr 28, 2021 22:18] | Mate in 2, 5 & 6 moves
 (= 7+2 )
Zeroposition
(a) +bc1 / e1 / g1 / d2 / f2 / a3 / e3 / b4 / f4 / a5 / c5 / b6 / a7 / c7 / b8 #2
(b) +bh2 #2 (2 solutions)
(c) +ba1 / b2 / c3 / d4 / e5 / d8 / e7 / h8 / h4 #5
(d) +bg7 #6
(e) +bg5 #6 (2 solutions)
| | | (2) Posted by Sarah Hornecker [Wednesday, Apr 28, 2021 23:40] |
CORRECTED AND EDITED POST, 29 April 2021!
Let me summarize this.
a:
 (= 7+17 )
Mate in 2
Each bishop is to be solved separately, not together on the diagram.
b:
 (= 7+3 )
Mate in 2, 2 solutions
Solutions: 1.d7, 1.h7 (mark to see)
c:
 (= 7+11 )
Mate in 5
Each bishop is to be solved separately, not together on the diagram.
d:
 (= 7+3 )
Mate in 6
e:
 (= 7+3 )
Mate in 6 (2 solutions)
Probable solution for d+e: 1.f7 Bxh6 2.e7+ Kg7 3.f8Q+ Kxg6 4.e8Q+ Kg5 5. ? (mark to see)
| | | (3) Posted by Roddy McKay [Thursday, Apr 29, 2021 16:59] |
There are actually 27 problems, including 15 #2 and 9 #5. Each has precisely 1 Black Bishop.
To avoid the hard work of posting 27 diagrams, I had used "/" as shorthand for "or", hope this helps.
R.M.
| | | (4) Posted by Sarah Hornecker [Thursday, Apr 29, 2021 17:06] |
Oh, apologies. Then there are not the cooks I had found. I misunderstood your notation. I edited above to clarify. I hope this is good with you.
| | | (5) Posted by Frank Richter [Thursday, Apr 29, 2021 17:49] |
Problem e) (bBg5) has duals in solution after 1.g7+ Kg8 2.f7+ Kh7 3.f8Q Kg6 4.g8Q+,g8R+,Qf7+; 3.- K:h6 4.g8Q+,g8R+,g8B+,Qf7 resp. 3.g8Q+ K:h6 4.f8Q+,Qh8+
| | | (6) Posted by Viktoras Paliulionis [Thursday, Apr 29, 2021 18:13] |
Correct direct mate problems should have only one solution.
The first twins are cooked if I understood the notation correctly:
a1) (+bBc1) 1.f7! 1.h7!
a2) (+bBe1) 1.f7! 1.h7!
...
Some twins have the same solution, why are such twins needed?
| | | (7) Posted by Roddy McKay [Friday, Apr 30, 2021 17:02] |
I had been relying on my own solving, clearly a long time without competing is taking its toll. Using popeye, the correct stipulations are now given.
(= 7+2 )
Zeroposition
(a) +bd2 / a3 / e3 / b4 / f4 / c5 / b8 #2
(b) +bc1 / e1 / f2 / g1 / a5 / b6 / a7 / c7 #2 (2 solutions)
(c) +bh2 #2 (3 solutions)
(d) +ba1 / b2 / c3 / d4 / e7 / d8 / h8 #5
(e) +bh4 #5 (2 solutions)
(f) +bg7 #6
(g) +be5 / g5 #6 (2 solutions)
The problem was intended as a humorous "task-like" effort, not to be taken too seriously.
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