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| (1) Posted by Hauke Reddmann [Friday, Dec 19, 2008 11:13] |
Hardest 2# in the world (NOT!!)
So, yesterday one of my club mates came in with this
(the one or other detail may be wrong):
Ka7 Qe7 Rd8 Rd1 Sc3 Sd5 Pb2 Pf2 Pd3 Pc4 Pc6 -
Kd4 Rc1 Rh5 Be4 Sg1 Pa6 Pg7
I solved it in one and a half minute (and this only
because it somewhat went against the "standard"
patterns of 2#) which still made me a new Einstein
according to the "manual".
Source? (Less that of the problem which isn't that
utterly brilliant either, but more of the Internet
meme virus declaring this to the "hardest problem"
ever". I can find half a dozen harder and better
ones in the Schiffmann book alone.)
Hauke
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| (2) Posted by Geoff Foster [Saturday, Dec 20, 2008 09:03] |
This one seems quite difficult. I don't know the source.
G W Chandler
 (= 6+7 )
#2
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| (3) Posted by Frank Richter [Saturday, Dec 20, 2008 18:29] |
The source is given in the Albrecht DB with The Problemist 1978.
The key is really fine, but not difficult to see.
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| (4) Posted by Axel Gilbert [Saturday, Dec 20, 2008 20:37] |
I would even say "the key is really fine, SO it's not difficult too see."
The first problem given is harder for the key is not that good.
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| (5) Posted by Hauke Reddmann [Wednesday, Dec 24, 2008 19:28] |
@Axel: Full ack, took me just a few seconds. Neat.
Hauke
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