|(1) Posted by Rewan Demontay (Real Name: J. Malcom) [Friday, Oct 4, 2019 23:36]; edited by Rewan Demontay (Real Name: J. Malcom) [19-10-05]|
The Double Square Vacation-In A Meredith!
After rereading Tim Krabbe’s #213, I started messing with double square vacations yesterday. I made a problem or two with 14 pieces. I wondered if the effect could be shown with just 12 pieces, aka a Meredith. But I didn’t want to have one piece occupy either square in accordance to a Black defense. I wanted each sqaure to be occupied by a different piece, as in Chris Handloser’s #5 Indian that shows the effect.
After some experimentation, I found success today. Thus I present the following.
(= 9+2 )
Solution: 1 0-0 a8=Q(R) 2. Ne1 Q(R)~ (Except for a3 and xe1) 3. Qh1+ ~ 4. Qx~#
Feel free to explore all of the possible variations yourself.
A threemover variation just because:
(= 9+4 )
Additionally, just for fun, I also took Loyd’s illegal position #4 with queenside castling and the BK’s position in Andreas Thoma’s double double square vacation and made a #3 out of it a combination of those two ideas.
(= 9+7 )
Solution: 1. 0-0-0 Ng4 2. Na1 ~ 3. Nb3# or 1... Nf1 2. Ne1 ~. 3. Nd3#
Also, has it ever been done with the castled rook moving to the king’s former sqaure? I did it myself.
(= 9+8 )
Solution: 1. 0-0-0 a1=~ 2. Bxa1 ~ 3. Re1 ~ 4. Re7# or 1... g2 2. Re1 a1=~ 3. Bxa1 ~ 4. Re7#
|(2) Posted by Siegfried Hornecker [Saturday, Oct 5, 2019 10:51]; edited by Siegfried Hornecker [19-10-05]|
Not a Meredith, but my rendering of the theme.
(= 9+10 )
Siegfried Hornecker, Original (composed 6 April 2006)
White to move and win
1.0-0! h4 2.Sh1 a5 3.Sf2 g6 4.Sd3 h3 5.Se1 Sd2 6.Sc2 mate
To my surprise I didn't find an old study of mine with the theme on the queenside. I thought I had tried that also, but seemingly not found any good position.
Apologies if this is anticipated a million times.
Also I'm not sure if some pawns can't be removed. In this form it should be correct, as the tries lead to a queen promotion but black has a draw thanks to stalemate.
|(3) Posted by Rewan Demontay (Real Name: J. Malcom) [Saturday, Oct 5, 2019 17:11]|
Nice study Siegfried!
Also, 10 cigars for anyone who can achieve a double square vacation with the basic set up below.
(= 3+0 )
Illegal positons are welcome.
|(4) Posted by Hauke Reddmann [Monday, Oct 7, 2019 12:53]; edited by Hauke Reddmann [19-10-07]|
(= 14+5 )
1.OOO dxc6/bxc6 2.Qe1/Qa1 ~ 3.Qa6/Qe6, dual Qe8 after c~
Illegal is for lamers - I hope I am no lamer :-) (At least the pawn structure seems
viable on first look - B captured the promoted h pawn and the other rook,
White only needs 7 captures.)
This is a proof of concept, I bet it can be done with less coke. :-)
(Question to the board - constructive black heaps run under the
moniker "coal mine", is there one for white heaps?)
(= 10+8 )
Wow. One dual and one piece less. Oh, and replace Sc2 with Pc2 for the
most WAT?! cook ever. :-)
|(5) Posted by Rewan Demontay (Real Name: J. Malcom) [Monday, Oct 7, 2019 13:57]; edited by Rewan Demontay (Real Name: J. Malcom) [19-10-07]|
Nicely done Hauke! I checked myself and it is indeed legal! We now have a new double square vacation type-a queen actually using the queenside! 10 cigars for you, ;-)!
EDIT: That is a really funny cook!
|(6) Posted by Jacques Rotenberg [Monday, Oct 7, 2019 17:18]; edited by Jacques Rotenberg [19-10-07]|
Martin W. Hoffmann
Idee und form 2009
(= 12+7 )
1…Kd5 2.Qe1 [3.Qh1‡]
1…Kb7 2.Qa1 Kc6,Kc8 3.Qa8‡
the fact that the Rd1 controls d4 is not really disturbing as shown in the try 1.Kf2? Kd5? 2.Qe1! Kxd4(Kc6) 3.Rd1(Qh1)# but 1...Kb7!
|(7) Posted by Rewan Demontay (Real Name: J. Malcom) [Monday, Oct 7, 2019 18:59]; edited by Rewan Demontay (Real Name: J. Malcom) [19-10-07]|
Thanks for that Jacques! I forgot to use the YACPBD matrix searcher. Sorry Hauke, I’m gonna have to confistictate your 10 cigars!
It turns out that it was shown as far back as 1930: www.yacpdb.org/#452724" target=_blank>https://www.yacpdb.org/#452724
Regős, Imre, Népszava (694) 1930-02-09, #3
(= 12+5 )
But it is cooked, and it anticipates Hauke’s first problem. But I’m sure that he could redeem himself (and ean his 10 cigars back!) by correcting Regos’s problem!
The first correct one, before Martin’s #3 (www.yacpdb.org/#442160" target=_blank>https://www.yacpdb.org/#442160) is from 1997: www.yacpdb.org/#58093" target=_blank>https://www.yacpdb.org/#58093
Ткаченко, Сергій Іванович, Die Schwalbe 1997, 3rd Prize, #3
(= 11+11 )
Also, also, I found the final form with a bishop on the queenside from 1929: www.yacpdb.org/#417579" target=_blank>https://www.yacpdb.org/#417579
Hartong, Jan, Tijdschrift van den Nederlandschen Schaakbond 1929, #4
(= 14+5 )
|(8) Posted by Rewan Demontay (Real Name: J. Malcom) [Monday, Oct 7, 2019 19:00]; edited by Rewan Demontay (Real Name: J. Malcom) [19-10-07]|
|(9) Posted by Hauke Reddmann [Monday, Oct 7, 2019 20:20]|
Being an almost militant nonsmoker, I can gladly live
without the cigars - thanks, Imre :-)
The Hartong is...impressive. Even I lacked imagination
to guess something is possible at all.
|(10) Posted by Rewan Demontay (Real Name: J. Malcom) [Monday, Oct 7, 2019 21:00]; edited by Rewan Demontay (Real Name: J. Malcom) [19-10-07]|
That’s fine. I’ll smoke’m out back! The Hartong is indeed impressive.
Also, I found a legal correction to the Remos problem.
J. Malcom, After Regős, Imre, Népszava (694) 1930-02-09, #3
(= 14+5 )
Now Nxd7 doesn”t work because the a7 blocks the queen’s rook from moving to a7.
But your 18 piece version is more elegant. and economical. What one dual is there that you mentioned?
|(11) Posted by Olaf Jenkner [Monday, Oct 7, 2019 21:49]|
To Hauke's question:
Kohlenkasten -- coal mine
Schneehaufen -- snow pile / snow heap
|(12) Posted by Joost de Heer [Tuesday, Oct 8, 2019 06:57]|
One could of course complain about the dual in the mating move in Hartong's position...
|(13) Posted by Hauke Reddmann [Tuesday, Oct 8, 2019 10:27]; edited by Hauke Reddmann [19-10-08]|
@Olaf: So I was spot on with the coke...sorta :-)
@Rewan: I wrote "one dual less", which means that,
since the first version has one, the second has none ;-)
(I confess the sentence was semantically ambiguous.)
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