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|(1) Posted by Andrey Selivanov [Tuesday, Dec 13, 2011 05:49]|
Olympic Chess Composing Tourney 2012
The International Chess Federation (FIDE) within the framework of its "Chess Composition" special project and in co-operation with the Turkish Chess Federation announce an Olympic chess composing tourney in 8 sections, dedicated to the World Chess Olympiad 2012 in Istanbul.
The tournament is co-ordinated with the WFCC Presidium and is a part of the joint efforts by FIDE and WFCC for the popularization and development of chess composition worldwide.
The tournament sections and judges are as follows:
A. Twomovers Judge: Anatoly Vasilenko (Ukraine)
B. Threemovers Judge: Miodrag Mladenović (Serbia)
C. Moremovers Judge: Yakov Vladimirov (Russia)
D. Endgame studies Judge: Oleg Pervakov (Russia)
E. Helpmates Judge: Nikola Stolev (Macedonia)
F. Selfmates Judge: Diyan Kostadinov (Bulgaria)
G. Fairies Judge: Juraj Lörinc (Slovakia)
H. Retros and Proofgames Judge: Bernd Graefrath (Germany)
In each section, only one composition from each author is acceptable; joint compositions are not allowed.
The themes are free in all sections, and any number of moves is acceptable in the h#, s#, fairies and retros sections. In the fairies section only problems computer-tested by one of the programs Alybadix, Popeye or WinChloe are allowed; the participants should mention the program they have used for testing their composition.
The director of the tournament is IGM Petko A. Petkov (FIDE international judge), who will not participate as author or judge in the tournament.
Entries (preferably in WORD format, but other formats are also acceptable) can be sent by e-mail only to the director's address at firstname.lastname@example.org
Participants should mention their postal address in the e-mail.
The closing date is May 1st, 2012.
The director will send all compositions to the judges on standardized anonymous diagrams by May 15th, 2012. All the judges should prepare their awards by July 15th, 2012.
The results will be published on the Internet by August 1st, 2012 and they will be declared final after two months allowed for claims of anticipation and unsoundness.
The best compositions in each section will be awarded with prizes, honourable mentions and commendations, as well as FIDE certificates and Olympic medals.
All participants will receive a copy of the booklet with the final awards.
|(2) Posted by Andrey Selivanov [Monday, Jul 30, 2012 10:47]|
Preliminary result in moremovers section - http://www.selivanov.ru/download/Awards/2012/OLYMP2012-more.pdf
|(3) Posted by seetharaman kalyan [Monday, Jul 30, 2012 17:01]; edited by seetharaman kalyan [12-07-30]|
Many outstanding problems have been awarded deserving prizes and awards. I have just one question. Some of the top placed problems show the 9-WCCT theme. Now that the WCCT entries are known, how the question of anticipation be decided ? This question may be relevant for the other sections of the FIDE tourney also.
|(4) Posted by Harry Fougiaxis [Wednesday, Aug 1, 2012 09:14]; edited by Harry Fougiaxis [12-08-05]|
Please refer to the relevant note in the WCCT-9 "entries booklet" PDF file, available for download at the WFCC site.
|(5) Posted by Sven Hendrik Lossin [Wednesday, Aug 1, 2012 10:50]|
Congratulations to Marcel Tribowski for an outstanding moremover who deserves the Gold medal.
|(6) Posted by Andrey Selivanov [Thursday, Aug 2, 2012 12:56]|
Preliminay result: Retro section - http://www.selivanov.ru/download/Awards/2012/OLYMP2012RETRO.pdf
|(7) Posted by Andrey Selivanov [Monday, Aug 6, 2012 06:55]; edited by Andrey Selivanov [12-08-06]|
section selfmates - http://www.selivanov.ru/download/Awards/2012/OLYMP2012Selfmate.pdf
section studies - http://www.selivanov.ru/download/Awards/2012/OLYMP2012EG.pdf
|(8) Posted by Olaf Jenkner [Monday, Aug 6, 2012 23:25]|
Note that the s#242 is terribly cooked.
The problem can be solved within 32 moves:
1. Da6+ Kb8 2. Da7+ Kc8 3. Sed6+ Kd7 4. Sd8+ Kxd8
5. Lxg5+ Txg5 6. Sxf7+ Kc8 7. Da8+ Kd7 8. Dd5+ Kc8
9. Dc6+ Kb8 10. Dc7+ Ka8 11. Te8+ Txe8 12. b7+ Ka7
13. b8=D+ Ka6 14. Dc6+ Ka5 15. Dbc7+ Kb4 16. D7b7+ Ka5
17. Dba6+ Kb4 18. Dcb7+ Kc5 19. Da5+ Kd4 20. Dd2+ Kc5
21. b4+ Kxc4 22. Sd6+ Kb3 23. Dbd5+ Ka4 24. b3+ Ka3
25. Da5+ Kxb3 26. Dda2+ Kc3 27. Dc5+ Kd3 28. Dcc4+ Ke3
29. Sf5+ Txf5 30. Da7+ Kd2 31. Dad4+ Ke1 32. Df1+ Txf1#
Even the position after the 232th move is cooked:
233. Dd8+ Le8 234. b8=D Kf7 235. De7+ Kg6 236. Dg5+ Kf7
237. e6+ Kxe6 238. Dbe5+ Kf7 239. Dgf4+ Kg6 240. Se7+ Txe7
241. Dff5+ Kxh6 242. Dxh5+ Lxh5#
237. ... Kf8 238. e7+ Kf7 239. Dbf4+ Ke6 240. Dff5+ Kd6
241. Sb7+ Kc6 242. Dd7+ Lxd7#
|(9) Posted by seetharaman kalyan [Tuesday, Aug 7, 2012 10:27]; edited by seetharaman kalyan [12-08-07]|
Selfmates: Though the prize winners are very good what impressed me was the 2nd HM by Mr.Azhusin. Wonderful double switchbacks. Great clarity and unity !
|(10) Posted by Andrey Selivanov [Tuesday, Aug 7, 2012 19:06]|
Preliminary result: section two movers -http://www.selivanov.ru/download/Awards/2012/OLYMP2012-2.pdf
|(11) Posted by seetharaman kalyan [Wednesday, Aug 8, 2012 09:04]|
Two movers award:
What is the theme of the 2nd HOn. Mention? In setplay and after a try, there are duals after two black defences. In two tries and after the key, these duals are avoided. I would hesitate to publish the problem (with the underused WQ)
|(12) Posted by Geoff Foster [Friday, Aug 10, 2012 00:38]|
The problem shows a doubling of the Ellerman/Makihovi theme: a black defence is met by two or more mates in one phase, then in other phases the mates are separated after this same defence. The problem also has two other phases in which neither of the dual mates occurs, with one of the thematic defences leading to a new mate, while the other thematic defence is the refutation!
|(13) Posted by Administrator [Friday, Aug 10, 2012 02:53]|
A friend who wants to remain anonymous writes:
Compare the Second Prize (2# section) with a much better
4th Com. The Problemist 1997/I (A7 in FIDE Album 1995-1997)
(= 6+8 )
1.Qh5? thr. 2.Sc5#, 1... Sf5,Bd5 2.Qh1,Qxg4#, but 1... d3!
1.Rd7? thr. 2.Rxd4#, 1... Sf5,Bd5 2.Sc5,Qxd5#, but 1... Sf3!
1.Rf7! thr. 2.Rf4#, 1... Sf5,Bd5 2.Qxf5,Sc5#
|(14) Posted by seetharaman kalyan [Friday, Aug 10, 2012 08:36]; edited by seetharaman kalyan [12-08-10]|
Wonderful Zagorijko with Dobrowskis paradox. Difficult combination with 2.Sc5 appearing as transferred mate also. Surprised at such a low award for this masterpiece
|(15) Posted by Andrey Selivanov [Saturday, Aug 11, 2012 07:43]; edited by Andrey Selivanov [12-08-11]|
Preliminary result in fairies section - http://www.selivanov.ru/download/Awards/2012/OLYMP2012FAIRIES.pdf
Preliminary result in helpmates section - http://www.selivanov.ru/download/Awards/2012/OLYMP2012-H.pdf
|(16) Posted by Administrator [Saturday, Aug 11, 2012 14:22]|
Addendum to post #13: Despite being very economical the position looked a little bit congested to me. Having had a better look I rearranged it (saving one black pawn) to a more open and to my opinion better setting:
(= 7+6 )
The solution remains the same except for mate Qf3 instead of Qh1. I think that usage of wPf2 instead of bPe3 is a delicate aesthetic touch!
|(17) Posted by seetharaman kalyan [Saturday, Aug 11, 2012 16:30]|
Well.... it is economical, but 1...Sf5 is now a selfblock in only one phase, losing the effect of echoing 1...Bd5, which is a selfblock in two phases and unguard in one phase.
|(18) Posted by Andrey Selivanov [Saturday, Aug 11, 2012 22:59]|
Preliminary result in three movers section http://www.selivanov.ru/download/Awards/2012/OLYMP2012-3.pdf
|(19) Posted by Sven Hendrik Lossin [Sunday, Aug 19, 2012 17:51]|
I'd like to comment Olaf Jenkners words.
I hope Mr. Ugren, Mr. Kostadinov and Mr. Rice wont resent me too much for this but I think this has to be said.
Mr. Ugren put a lot of creativity in his very long selfmates but completely misses the minimum requirement for these ultralong selfmates to work: White has to be very weak and Black at best very strong.
If this minimum requirement is not fulfilled, white will always force selfmate by the following strategy:
- Win all the black pieces but one pawn that is best placed on a,b,g or h-file.
- Force this pawn to mate.
I am sure that all people that are problemists and OTB-player with a considerable strength of about 2200 ELO or even less will be able to perform this in the given position in less than a hundred moves always giving black only a single move. Gustav is even better and needs less than forty.
Although the judge Dijan Kostadinov expressed some doubts, I still think that you can never include this one in an award since the probability that it works is simply 0 percent. I think it is a matter of instinct for what can work and what can't and my instincts told me that this can never work.
Even worse is the case in the recent s#164 in the July 2012 problemist that I (and I have not a single idea about the science of cooking) cooked in less than an hour in 37-moves and now have a solution in 21. White is much too strong there and it is even surprising that white needs more than 20 moves.
One more sentence: Marcel Tribowski had some very great selfmates with 18-30 moves. You can get an idea how hard he sometimes had to fight for getting them correct by looking for them in the PDB, for example P1089005. I think that it is worth to have a look at these fights for getting a feeling about that issue. And it is a nice crime story as well ;)
|(20) Posted by Joost de Heer [Sunday, Aug 19, 2012 18:29]; edited by Joost de Heer [12-08-19]|
It reminds me of a quote I once heard: There are two kinds of illegal cluster positions: Cooked ones and ones that haven't been cooked yet.
I know that Michel has a limit of one non-computertested proofgame for his Champagne tourney during meetings, because he received dozens of compositions that were obviously cooked but where the cook wasn't obvious, and he didn't feel like wasting time to find those cooks on something that would never get a prize anyway.
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