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MatPlus.Net Forum General Looking for mutual caterpillar problema

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Krabbé's article De Rups is in Schaakbulletin 183, februari 1983, with 19 examples. Let me see if I manage to operate the scanner.

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I knew it!

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Krabbé does not have a mutual Rups, but there is Korolkov's yacpdb 275818.

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Even if Krabbe has no mutual caterpillars, it would still be nice to see that article.

And thanks for that double caterpillar pro life by Korolkov Joosr! I was looking for such a problem as well!

A long caterpillar problem that I know is a n#24 made by John Nunn that features 9 consecutive corner-to-corner moves. It can found in Morse's book

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Doesn’t that Nunn problem show 18 consecutive corner-to-corner moves? Mark Kirtley and myself have composed selfmates showing 27 consecutive corner-to-corner moves (by bishop and queen respectively).

What about this one?

Ronald Turnbull
Special Prize CCC Challenge 1991
(= 11+12 )

Draw

1.c7+ Kxc8 2.Bh1 then White plays Ba8/h1 while Black moves his rooks, avoiding repetition, and moving a pawn every 50th move until 452.Bh1 R~ drawing by the 50-move rule. The introductory play is significant in that Black's first move being a capture starts the count for the 50 move rule.

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The above mentioned problem is here:

http://pdb.dieschwalbe.de/search.jsp?expression=probid=%27P1341253%27

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Thanks for those problems! And here is a link to that Nunn problem that I mentioned in yacpdb: https://www.yacpdb.org/#3

Here the diagram for your convenience. And yes, the solution does contain 18 consecutive corner-to-corner moves with a White light-sqaures me bishop.

John Nunn, 1991, n#24

(= 6+10 )

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Let me share the following (fairy) problem showing "rook-caterpillar".

Bojan Bašić
2nd Prize, Springaren Winter Tourney 2014-15
(= 12+8 )
s#7
Circe Parrain
1+0 Ubi-Ubi

Solution: 1.Re7*e8 + Ka7-a6 [+bSe7] 2.Re6*e7 + Ka6-a5 [+bSe6] 3.Re5*e6 + Ka5-a4 [+bSe5] 4.Re4*e5 + Ka4-a3 [+bSe4] 5.Re3*e4 + Ka3-a2 [+bSe3] + 6.Re2*e3 + Ka2-a1 [+bSe2] 7.Sd1*b2 Ka1-a2 [+bBb3] #

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Many of the problems along the Bláthy (e.g. P1188172) - Speckmann - Miljanic (P1251710) line include caterpillars, but surely it makes sense to differentiate between these forced marches and problems where they serve some positive purpose.

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Ah, but if Whites march wouldn't be forced, the problem would be cooked,
if Blacks march wouldn't be forced, the problem would be unsolvable :-)
Is "forced only by zugzwang" what you mean?

P.S. Just remembered my problem from the Uelzen SCHWALBE congress:

(= 2+6 )

#6

I think this is "forced" by your definition?!

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Yes of course in a correct problem all moves are forced… so yes, forced by zugzwang, although I think there are a couple of problems where Black delays the mate as much as possible by moving the caterpillar, and not a non-caterpillar pawn.

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Hauke, what is exact source of your #6?

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@Marjan: a bit complicated. 1995 was the yearly conference of the SCHWALBE
in Uelzen. Together with the local chess club, they brought out a special issue
of the club zine, the (Schach)Kiebitz (very clever, both are birds - and
a Kiebitz is a spectator at chess), and a few problems were made
especially for the occasion. So "H. Reddmann, Schach-Kiebitz, 1995".

EDIT: Should add what Northern Germans call a "Döntsche", just for teh lulz.

I sent in three problems, all somewhat symbol-looking, a German triangle stop sign,
an arrow, and this one, and accompanied them with the quip: "Attention,
there lies Uelzen!" The club introducer to the problems topped it by stating
the "U" looks rather distorted, surely due to the many traffic-related construction
sites in the Uelzen inner city :-)

Hauke

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(34) Posted by Marjan Kovačević [Sunday, Jul 21, 2019 22:12]

Thanks, Hauke! I have reproduced it in the daily Politika.

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Interestingly, the 27 corner-to-corner moves for the Queen, and the 28 for the Bishop, seem to he selfmate records where the piece in question makes consecutive moves between two different squares, aka a pendulum.

I wonder, what are the records for the Rook, Knight, and King?

I managed to make some long ones on my own.

Rook:

WTM,s#23

(= 5+12 )

Knight:

WTM, s#25

(= 5+11 )

King:WTM, s#23

(= 3+12 )

And just for a complete list:

Queen:

Michael McDowell
S2669 The Problemist 26-5, p. 190, 09/2017

P1341253, WTM, s#27

(= 6+12 )

Bishop:

Selfmate in 28
Mark Kirtley
The Problemist, 1994

Found In Tim Krabbe's Diary, #106: https://timkr.home.xs4all.nl/chess2/diary_6.htm

WTM, s#28

(= 7+11 )

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I found a new high number for the rook pendulum, afaik, that is more than my s#23 from above.

WTM, s#26

(= 5+12 )

And a slighy improved king’s pendulum.

s#24

(= 3+12 )

Records for directmate pendulums can be found here: http://superproblem.ru/htm/composition/articles/stat64.html

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MatPlus.Net Forum General Looking for mutual caterpillar problema