|(1) Posted by Hauke Reddmann [Tuesday, Mar 26, 2019 19:59]|
Visserman's cyclic Nightrider Plachutta
Am I stoopid or is the 1684 in Milan's encyclopedia misprinted?
(= 9+12 )
(a3=G, d1,g2,g4=N) 1.Sh4!
Obviously, Nd1-e3 compensates against Rc4 and Ng4-e3 against Nxf5. But what is the
reason White can, after Ng2-e3, not play Sc2+ and Sxf5+ in any order?
(flash of ingenuity - Rb1 is a G?)
|(2) Posted by Juraj Lörinc [Tuesday, Mar 26, 2019 22:18]|
After 1...N2e3 you want to checkmate by 3.Rc4+, but 2.Sc2+ closes the rook line.
|(3) Posted by Siegfried Hornecker [Wednesday, Mar 27, 2019 11:34]|
Ng4 defends c2 if you play Nf5+ first?
|(4) Posted by Juraj Lörinc [Wednesday, Mar 27, 2019 18:38]|
1...N2e3 2.Sxf5+ Nxf5 3.Rc4# (not 2.Sc2+? Nxc2 3.Rc4??)
|(5) Posted by Hauke Reddmann [Wednesday, Mar 27, 2019 22:04]|
Of course. Confused it with the Keller paradox mechanism.
OTB players shouldn't touch nightriders :-)
|(6) Posted by Juraj Lörinc [Wednesday, Mar 27, 2019 23:31]|
Quite opposite. OTB players are welcome to try fairy pieces, many of them, to familiarize and understand - and perhaps to start using them.
|(7) Posted by Kostas Prentos [Thursday, Mar 28, 2019 07:11]|
Obviously it's too late to do anything about it, but I always thought OTB chess would be more interesting with Nightriders instead of Knights. Even if 1.e4 would not be playable anymore.
|(8) Posted by Jacques Rotenberg [Thursday, Mar 28, 2019 13:45]|
another example of Wurzburg-Plachutta with Nightriders and cyclic variations :
The British Chess Magazine 1979
(= 9+12 )
1…N4f5 2.Se3+ N×e3 3.Qd6‡
1…N3f5 2.Qd6+ N×d6 3.Se7‡
1…N6f5 2.Se7+ N×e7 3.Qd4‡
1…N7f5 2.Qd4+ N×d4 3.Se3‡
|(9) Posted by Jacques Rotenberg [Thursday, Mar 28, 2019 15:42]|
Die Schwalbe 2004
(= 13+11 )
...... = lion
1…Nbc3 a 2.RLe3+ A N×g1/RLf2 3.Rd6/Nf3‡ - The RLe5 must move in order to forbid the RLh5 to control d5
1…N2c3 b 2.Rd6+ B Nd5/RLd5 3.R×e4/LI×h8‡ - The Rg6 must move in order to forbid the BLh7 to control e4
1…N4c3 c 2.R×e4+ C N×e4/BL×e4 3.RLe3/LI×h8‡ - The Rf4 must move in order to forbid the RLf7 to control f2
1.BLf5! [2.c3+ Nb×c3,N2×c3,N4×c3 3.Nc2‡]
1…Nbc3 a 2.R×e4+ C N×e4 3.Rd6‡ - The RLe5 must stay in order not to allow the RLh5 to control d5
1…N2c3 b 2.RLe3+ A N×g1 3.R×e4‡ - The Rg6 must stay in order not to allow the BLh7 to control e4
1…N4c3 c 2.Rd6+ B Nd5 3.RLe3‡ - The Rf4 must stay in order not to allow the RLf7 to control f2
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