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(1) Posted by Miodrag Mladenović [Monday, Nov 13, 2006 21:24]; edited by Miodrag Mladenović [06-11-24] |
2ND ECSC - Problems Here are the problems from the 2nd ECSC tournament. I listed below only 14 problems because there are 4 originals. I'll post solutions few days later in case that you cannot solve problems. Enjoy solving if you did not participate.1. Jozsef Szoghy 3. Pr. Magyar Sakkelet 1972 | 2. Hugo Knuppert 4. Pr. Schweizerische Schachzeitung 1963 | 3. Jean P. Boyer Europe Echecs 1982 | (= 9+9 )
| (= 10+11 )
| (= 11+10 )
| #2 | #2 | #2 |
| 4. Venelin Alaikov 1.H.M. Buletin Problemistic 1990-1991v | 5. Percy Blake 1. cena Aftonbladet 1906 | 6. R. Rupp Schach Expres 1949 | (= 11+9 )
| (= 10+11 )
| (= 11+12 )
| #3 | #3 | #3 |
| |
7. Ernest Pogosjanc Sachmaty v SSSR 1976 | 8. M. Klinkov 3. Comm. JT Minsk 1967 | 9. G. Kasparjan A.Gurvic New Statesman 1960 | (= 5+3 )
| (= 6+5 )
| (= 8+6 )
| + | + | + |
| 10. Shlomo Seider 3. Pr. Solidarita Tourney 1989 | 11. Petko Petkov original | 12. Petko Petkov original | (= 9+10 )
| | | S#2 | S#3 | S#5 |
| 13. Karel Traxler 1. Pr. BCM 1900 | 14. O. Postnikov 4. Pl. KMS Tourney 1991v | 15. St. Schneider H. Grasemann 3. H.M. Deutsche Schachblatter 1979-1980 | (= 7+8 )
| (= 9+12 )
| (= 6+10 )
| #4 | #5 | #6 |
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| 16. Branislav Djurasevic 5. Pl. Liga problemista 1984 | 17. Christopher Jones original for Pat a mat 2006 | 18. Chris. Feather original | (= 8+12 )
| | (= 4+4 )
| H#2 4.1.1.1 | H#3 2.1.1.1.1.1 | H#6 1 solution | |
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(2) Posted by Harry Fougiaxis [Monday, Nov 13, 2006 22:42] |
Thanks, Misha, for the material and congratulations on Serbia's 1st place and your own very good result. An off-topic question, is there any easy way to have diagrams appearing in a table the way you did? I know basic html (at least all what I needed so that to build the Halkidiki and Eretria WCCC sites). |
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(3) Posted by David Knezevic [Tuesday, Nov 14, 2006 01:26] |
Harry: "... is there any easy way to have diagrams appearing in a table ... ?"
I think that I should answer this question. At the moment the only way is to use html markups, but the care must be taken about newline characters. Current (rather primitive) text rendering module replaces all newlines with to html <br> tag. Therefore, within a table the hard line breaks are harmless only inside the <td> ... </td> object. If line is broken at logical location, e.g. :
...(some text)</td>[NL]
<td>(text...)
you will not get the expected result. For instance, IE will move ALL such linebreaks in front of the entire table making sometimes a pretty big lead above it.
I have been planning a completely new text rendering for several weeks, but I want it to do it right - and it requires more time than I can spare now. However, I will do some fixes in current module just to prevent this peculiar linebreaks behaviour and maybe to ease table creation (for instance to type ^t instead of </td><td> or ^r instead of </tr><tr>, some shortcuts like that). |
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(4) Posted by Miodrag Mladenović [Tuesday, Nov 14, 2006 07:12] |
Harry, thanks for your congrats. As Milan already answered the only problem is with a new lines. I first typed well formatted HTML text. But then at the end I had to remove new line characters at the end of lines. Otherwise, each new line character generates one blank row in front of table. I'll send you through an email HTML text that I had to type to create table from above. I thought to type it here but it's not possible because it will display it incorrectly. |
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(5) Posted by Frank Richter [Tuesday, Nov 14, 2006 12:46] |
Are the results of the composing tourneys already published? |
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(6) Posted by Branislav Djurašević [Tuesday, Nov 14, 2006 15:30]; edited by Branislav Djurašević [06-11-15] |
Congratulations for 1st place for Serbia team!!
I am pleasantly surprised that one of my problem (5.Pl.Liga Problemista 1984, h#2, 4111, 8+12) was among others for solving competition and as I can see from solvers table some of them could not solve it.
Problem shows 4 different ways of unpinning black bishop in combination with bishop star.
But I must put remark, because I am real author of this problem, not my father Bozidar as it was written above the diagram and it is general mistake what appears often with some of my problems recently!
In fact, my father Bozidar who is international chess master from 1957, born 1933 and in relatively good condition nowadays, composed only one published problem (mate in two) in Yugoslav chess journal "Sah" 1949!?
So, all other problems which have been reproduced in chess problem history with family name Djurasevic is mine (as far as I know) until my sons Dejan and Kira will start to compose!? I was born in 1957, three days after Marjan Kovacevic and one day after Michel Caillaud (in a very good company!).
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(7) Posted by Miodrag Mladenović [Tuesday, Nov 14, 2006 18:25] |
Frank, results of composing tourneys are published too. There are too many diagrams and I do not have them in electronic form. However I checked your problems and you've got I/II Prize for your S#2 (wKf1/bKb5). You also won 2nd HM for your S#3 (wKe8/bKd5). Congratulations! I am sure you will gat a booklet later on from organizers. |
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(8) Posted by Administrator [Tuesday, Nov 14, 2006 20:30] |
(last digression here)
I think now from now on it will be easier (if not trivial) to format tables - See more... |
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(9) Posted by Frank Richter [Wednesday, Nov 15, 2006 09:30] |
Dear Misha,
many thanks for the good information. I will stay for the booklet.
I like to return the congratulations on your excellent solving results! |
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(10) Posted by Miodrag Mladenović [Thursday, Nov 23, 2006 07:15] |
I've got an email from Chris Feather. He is not planning to publish his H#6 anywhere else so he asked me to add diagram of his problem. |
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(11) Posted by Miodrag Mladenović [Thursday, Nov 23, 2006 07:31] |
Please note that I update name of H#2 Author. Branislav Djurasevic confirmed for me that this is his problem and not a problem of his father Bozidar. |
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(12) Posted by Miodrag Mladenović [Saturday, Nov 25, 2006 07:24] |
Solutions:
Here are solutions of all problems:
1. 1.Qg3:!
2. 1.Rc6!
3. 1.Sf5!
4.
1.Rd1! (2.Sd2+)
1...Kd5: 2.Qg8+
1...dc6: 2.Sc5+
1...g6 2.Qe5+
5.
1.Qh3! (2.Sd3!)
1...ef6: 2.Qf5+
1...e6 2.Sg4
1...bc5: 2.Bd1
1...Se6 2.Le6:
6.
1.Kb7! zz
1...Ba~ 2.Rd5
1...Se7 2.Te5
1...Bg7 2.Rf5:
1...Bh8 2.Rf5:
1...Rg4 2.Bf5:+
1...Rh5: 2.Rf5:
1...c3 2.Rc3:+
1...f4 2.Rg5:
7.
1.Sb5+! Kc6: 2.ef7: Kd7+ 3.Kf2 Ke7 4.Sc7 Lh1
5.Kg1 L~ 6.Se6+
8.
1.Bd6+! Rd6: 2.b8Q Ra6:+ 3.Ka6: d2+
4.Ka5 d1Q 5.Qb6+ Kc4 6.Se5+ Kc3
7.Qb4+ Kc2 8.Qa4+ K~ 9.Qd1:+ Kd1:
10.Sg4! Bc4 11.Se3+ Ke2 12.Sc4: h4
13.d6 h3 14.d7 h2 15.d8Q h1Q
16.Qd2+ Kf1 17.Se3+ Kg1 18.Qe1+ Kh2
19.Qh4+ Kg1 20.Qg3+
9.
1.Bc3! dc3: 2.Kf8 Db4+ 3.Kf7 Bh5+
4.g6 Bg6: 5.Rg6: Kh7 6.Rg4 Kh6
7.Rh4+ Kg5 8.f4+ Kf5 9.de4:+ Qd4:
10.g4+ Kf4: 11.g5+ K~ 12.Rd4:+ Kd4:
13.g6+
10.
1.Sc6? Qa1!
1.Sc2? Sf1!
1.Se2? Qa4!
1.Sb3! (2.Qd3:+)
1...Qa1 2.Qe5+
1...Sf1 2.Se3+
1...Qa4 2.Sf4+
13.
1.Sf5! (2.Re3+ fe3:/Kd5 3.Sd6+/Bf7+)
1...Kd5 2.Rd3:+ Kc4/Ke4 3.Sd6+/Bg6+
1...Bf5: 2.Rd3: ~/Kd3:/Bg4 3.Bf3+/Qc3+/Bg6+
1...cb4: 2.Qd4+ Kf5: 3.Re3
1...d2 2.Rc3 d1Q/f3 3.Sd6+
14.
1.Bg2! (2.Be4:#)
1...Sf2 2.Sb4+ Kd4 3.Sa2+ Kd5 4.Rac4
1...Rh4: 2.Sc7+ Kc5 3.Se8+ Kd5 4.Rcc4
15.
1.Rb8! (2.Qg8:+ Kg8: 3.Bg6+)
1...Rc3+ 2.Kb4 Rc4+ 3.Ka5 Rc5+
4.Rb5 Rc7 5.Qh6:+
16.
i) 1.Re4 b5 2.Bc6 bc6:#
ii) 1.Qg5 Ra6 2.Be6: Re6:#
iii) 1.c5 ed3: 2.Be4 d4#
iv) 1.Ke6: e4 2.Bc4 Bc4:#
18.
1.Re1: Sb3:+ 2.Kc2+ Sc1 3.Re5 Se2
4.Kb3 Sd4+ 5.Ka4 Ka2 6.Ra5 b3#
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