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| (101) Posted by Miodrag Mladenović [Friday, Mar 25, 2022 10:52] |
@(99) There is a cook:
1.Rc6 2.Rxc7 3.Rxc8 4.Rxb8 5.Rxb7 6.Rxd7 7.-10.Kc6 11.-12.Rc5 13.-14.Qd7+ Qxd7#
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| (102) Posted by Dragan Stojnić [Friday, Mar 25, 2022 15:29] |
(deleted)
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| (103) Posted by Frank Richter [Friday, Mar 25, 2022 16:16] |
Well, also should work 7.Rg6 8.Rd6 9.R:d7 10.Qb1 11.Q:b7 12.Q:b8 13.Q:c8 14.Kc6 15.Rd5 16.Rc5 17.Qd7+ Q:d7# (checked on screen only).
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| (104) Posted by Dragan Stojnić [Friday, Mar 25, 2022 16:44] |
(deleted)
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| (105) Posted by Olaf Jenkner [Friday, Mar 25, 2022 16:57] |
Cooked:
5. hxh8=S 6.Qb1 7.Qxb7 8.Qxc7 9.Sxe7 10.Sc6 11.Sxb8 12.Sxd7 13.Kc6 14.Sb6 15.Sxc8 16.Qd7 Qxd7#
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| (106) Posted by Miodrag Mladenović [Friday, Mar 25, 2022 17:36] |
@Dragan(102)
How is this position different then the position I gave in (16) ser-S#17. Now you did not provide the diagram but based on the notation I would say it's the same position as in (16). And yes the cook has been already published in the post (17). I recommend that you first check what has been done so that we avoid the duplicate posts of the same problems.
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| (107) Posted by Joost de Heer [Friday, Mar 25, 2022 20:56] |
 (= 3+16 )
ser-!#12 'Popeye rules' (C+)
1. Sg3 2. Sf5 3. Se7 4. Sc8 5. Se7 6. Sc6 7. Sb8 8. Sa6 9. Sc5 10. Sb7 11. Ka6 12. Ka7!#
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| (108) Posted by Joost de Heer [Friday, Mar 25, 2022 23:21] |
QUOTE
I add the condition "KKK" (Kein Königs-Kontakt) to my problem, in English MMM (Majesties Mustn't Meet) :)
Winchloe has this as 'Les Rois ne doivent pas être en contact'.
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| (109) Posted by Olaf Jenkner [Friday, Mar 25, 2022 23:35] |
The next version of Gustav will have the switch "KKK" on/off .
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| (110) Posted by Dragan Stojnić [Saturday, Mar 26, 2022 00:07] |
Scheme for ser s=26?
White Kg1 Qf1 Rb6 Rd6 Bf2 Bh3 Pa3 b5 c6 h2
Black all 16 in homebase
sol. 1.Bg2 6.gxh8B 8.Bxe7 9.Bxd8 10.Bxc7 11.Bxb8 12.c7 13.Bxb7 14.Ba6! 15.Rb7 16.Bxa7 21.Kb6 22.Rd4 23.Ra4 24.Ra5 25.a4 26.Qxf7+ Kxf7=
If 14.Bxa8? then are need 27 moves (22.Ka5 23.Ra6 24.Kb6 26.a5)
How many is really to be correct?
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| (111) Posted by Olaf Jenkner [Saturday, Mar 26, 2022 00:42] |
It's time for a fifth interim balance. (EDIT 03/26 12:12)
Section ser-s= is a little bit confusing.
(81), (87) and (110) are cooked.
Solution of (91):
1. Bg2 2. h4 3. h5 4. h6 5. hxg7 6. gxh8B 7. Bf6 8. Bxe7 9. Bxd8 10. Bxc7 11. Bxb8 12. c7 13. Bxb7 14. Bxa8 15. Rb7 16. Bxa7 17. Rd6 18. Kd2 19. Kc3 20. Kb4 21. Ka5 22. Ra6 23. Rb6 24. a5 25. Qxf7 Kxf7=
(94) is cooked.
Solution of (118)
1.Bg2 6.gxh8B 8.Bxe7 9.Bxd8 10.Bxc7 11.Bxb8 12.c7 13.Bxb7 14.Ba6! 15. Qxa8 16. Rb7 17.Bxa7 22. Kb6 23. Rd4 24. Ra4 25. Ra5 26. a4=
Current records are:
ser-s# ..16 .......... (88) Michael Schreckenbach
ser-s= ..25 .......... (91) Miodrag Mladenović (C?)
Ser-h# .11 .......... (42) Michel Caillaud / Arno Tüngler
Ser-# ...11 .......... (39) Arno Tüngler (starter)
Ser-!= ..26 .......... (118) Dragan Stojnić (C?)
Ser-!# ..12 .......... (107) Joost de Heer
Ser-!# MMM 14 .. (74) Frank Richter
Ser-!# MMM 14 .. (78) Joost de Heer
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| (112) Posted by Miodrag Mladenović [Saturday, Mar 26, 2022 07:08] |
blank
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| (113) Posted by Michel Caillaud [Saturday, Mar 26, 2022 07:09] |
Objection to the ser-s= scheme by Dragan.
Dragan's scheme is with wPc7 after capture of bQd8. Cooking scheme is with wRc7 pinned by bQd8
(110)
1.ç×b7 2.b×ç8=N 3.Rdç6 4.R×ç7 5.Bg2 6.B×a8 7.Rbb7 8.B×a7 9.B×b8 10.h4 11.h5 12.h6 13.h×g7 14.g×h8=Q 15.Qhf6 16.Qa6 17.Qf2 18.Qfa7 19.Kf2 20.Ké3 21.Kd4 22.Kç5 23.Kb6 24.a4 25.a5 26.Nd6+ é×d6=
EDIT : Ah! Miodrag was 1 minute quicker than me!
(94)
1.Bf6 2.B×é7 3.R×d7 4.Qa5 5.Qa6 6.Kd2 7.Kç3 8.Kb4 9.Ka5 10.R×ç7 11.B×ç8 12.B×b7 13.B×a8 14.Rbb7 15.Bç5 16.B×a7 17.B×b8 18.h4 19.h5 20.h6 21.h×g7 22.g×h8=B 23.Bd4 24.Bda7 25.Kb6 26.a4 27.a5!=
As the cooks are in just the number of moves, maybe there is some way to make Dragan's scheme working avoiding the cooking scheme...
Here is an exploitation of the cooking scheme (certainly not a record...)
 (= 9+16 )
ser-s=22
1.Bé4 2.d4 3.d5 4.d6 5.d×ç7 6.ç×b8=B 7.Rç7 8.ç4 9.ç5 10.ç6 11.ç×b7 12.b×ç8=N 13.Bb7 14.Ba6 15.Rbb7 16.Bf×a7 17.Kf2 18.Ké3 19.Kd4 20.Kç5 21.Kb6 22.Nd6+ é×d6=
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| (114) Posted by seetharaman kalyan [Saturday, Mar 26, 2022 07:31] |
Can't understand how the ending position in 112 is stalemate? Can't the c7 pawn capture d8?
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| (115) Posted by Miodrag Mladenović [Saturday, Mar 26, 2022 07:39] |
You are right, my mistake.
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| (116) Posted by Miodrag Mladenović [Saturday, Mar 26, 2022 08:35] |
blank (incorrect)
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| (117) Posted by Frank Richter [Saturday, Mar 26, 2022 08:42] |
 (= 4+16 )
ser-s#18, C?
1.Sd5 2.f4 5.f:g7 6.g:h8R 7.R:g8 8.Rg6 9.Ra6 10.R:a7 11.R:a8 12.R:b8 13.R:b7 14.Ka6 15.Ka7 16.Rb8 17.Ra8 18.S:c7+ Q:c7#
A wBh6 would be possible too. It's still testing ...
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| (118) Posted by Dragan Stojnić [Saturday, Mar 26, 2022 08:46] |
However I hope (110) without Qf1 then it is ser-!=25. Right?
(Caillauds cook now no exist)
After found cook in (94) record stay on 25 ago...
Also if in (110) put White Qh1(instead f1) maybe can ser-!=26:
14.Ba6 15.Qa8 16.Rb7 etc. 26.a4=
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| (119) Posted by Olaf Jenkner [Saturday, Mar 26, 2022 09:51] |
(117) is cooked.
7. Kb4 8. Kc3 9. Kd4 10. Sg4 11. Se5 12. Sxd7 13. Ke5 14. Rg4 15. Re4 16. Sf4 17. Sf6 exf6#
With wPh6 cooked as well:
7. Kb4 8. Sb6 9. Sxd7 10. Rxh7 11. Rxf7 12. h7 13. hxg8Q 14. Rf5 15. Rb5 16. Kc5 17. Qc4 18. Sf6 exf6#
With wBh6 cooked as well:
8. Rg4 9. Sb6 10. Sxd7 11. Kb4 12. Re4 13. Bf4 14. Kc3 15. Kd4 16. Ke5 17. Sf6 exf6#
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| (120) Posted by Frank Richter [Saturday, Mar 26, 2022 10:19] |
Then one move less (would be still a record):
 (= 4+16 )
ser-s#17, C?
1.f4 4.f:g7 5.g:h8R 6.R:g8 7.Rg6 8.Ra6 9.R:a7 10.R:a8 11.R:b8 12.R:b7 13.Ka6 14.Ka7 15.Rb8 16.Ra8 17.S:c7+ Q:c7#
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