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MatPlus.Net Forum General Plachutta in 2#
 
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(1) Posted by Hauke Reddmann [Thursday, Mar 22, 2007 16:08]

Plachutta in 2#


Do you know nice examples of the Plachutta theme in 2#?
(I even just managed to do a 180 degree Plachutta!
- Of course with a checking key. Probably this is not
needed in the standard 90 degree case.)

Hauke


 
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(2) Posted by Milan Velimirović [Thursday, Mar 22, 2007 17:14]

Black or White Plachuta? Black is hardly possible in a twomover since theme requires two moves: 1) interference and 2) Decoy.

For White Plachutta a black sacrificial move is missing before the first white move - or is it?
 
Miroslav Stošić
original from 1973
Kd5 Qb8 Rc1 c8 Bf1 h8 Sd2 f2 Pb5 c2 c5 e2 f3 f5 g2 g3 - Ke3 Pe5 (16+2)#2 vv
 



1.Qxe5+? Kxd2 2.Qf4#, 1... Kxf2! 2.Bd4??
1.Bxe5? (~) Kxf2 2.Bd4#, 1... Kxd2! 2.Qf4??

1.fxe6(ep)! (~)
1... Kxd2 2.Qf4#
1... Kxf2 2.Bd4#

Pawn sacrifice was the last black move before the position on diagram.
This original from 1973 was reproduced in book: "Miroslav Stošić - Izabrani problemi" (1979)

 
 
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(3) Posted by Hauke Reddmann [Friday, Mar 23, 2007 12:22]

Yup, the black sacrifice was "just" in the past here -
extremely cool problem!

No, I meant black Plachutta or Holzhausen, and no, you don't need
a decoy for either: wBa8,wRb7,sRb6,sRc7,sKd5, 1...R(x)c6 2.Rb5/d7
Although the effect is rather more related to a Nowotny. I dimly remember
Brunner used that matrix. Or was it Kraemer/Zepler?

Hauke
 
   
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(4) Posted by Harry Fougiaxis [Friday, Mar 23, 2007 23:38]; edited by Harry Fougiaxis [07-03-23]

Well, I had the impression that Plachutta needs a decoy, by definition. Yet, I see what you mean (although I do not personally consider it a Plachutta). You will not be surprised, I guess, that this has been done quite a few times, see the below problems that I found in the WinChloe database.

Francis J.C. de Blasio
Problem 1953
Ka2 Qg8 Rb6 f7 Be1 h1 Sc2 d8 Pb4 e2 - Kc4 Qe7 Rf6 g6 Pc7 f4 g4 (10+7)#21...Qxb4 2.Rxc7#

1.Se6! [2.Sa3#]
1...Qxe6 2.Rxc7#
1...Rxe6 2.Rxf4#
1...Qxb4 2.Rxb4#
1...f3 2.Se3#

It seems to be the pioneer, but I'm not a two-mover expert!

Jacques Rotenberg
Matthieu Leschemelle
Europe Echecs 1995
Kg2 Qc2 Rc5 Be7 Sa2 d4 - Ka3 Qb7 Rb5 c4 Pc3 c6 (6+6)#21.Sb4! [2.Qb3#]
1...Rcxb4 2.Rxc3#
1...Rbxb4 2.Ra5#
1...Kxb4 2.Rxb5#
(1...Rxd4 2.Rxc3#)

The same mechanism, but in Meredith and with a flight-giving key

Jacques Rotenberg
Belfort WCCC 1994
Kh4 Qe3 Rb7 e6 Bg8 Sc2 c3 Pa2 a4 b5 c7 - Kc4 Rd6 e5 Bd8 Pa5 a7 c6 e4 e7 h5 (11+10)#2vv1.bxc6? [2.Sa3#] 1...Rb5/Rd4 2.Rxe4/Qxd4#, but 1...Rd3!

1.Sxe4? [2.Qb3#] 1...Rd3/Rxe4+ 2.Rxc6/Rxe4#, but 1...Rxb5!

1.Sd5! [2.Qd4#]
1...Rdxd5 2.Rxc6#
1...Rexd5 2.Rxe4#
1...Kxd5 2.Qd4#
1...c5 2.Qb3#

Jacques Rotenberg
Jean-Marc Loustau
2 Pr Problemesis 1999-2002
Kg7 Qb6 Rd6 h4 Be1 g4 Sc5 f6 Pc2 - Kc4 Qf3 Ra7 g1 Ba3 f5 Se2 g6 Pb7 e3 (9+10)#2v...1.Scd7? [2.Qb3#] 1...Qd5 2.Bxe2#, 1...Bxc2 2.Be6#, but 1...Bxd6!
1.Se6? [2.Qb3#] 1...Bxd6 2.Qb3#, but 1...Bxc2!
1.Sd3? [2.Qb3#] 1...Bxd6 2.Sb2#, but 1...Qd5!

1.Sce4! [2.Qb3#]
1...Bxe4 2.Be6#
1...Qxe4 2.Bxe2#
1...Bxd6 2.Sxd6#
(1...Bb4 2.Qxb4#, 1...Sd4,Sc1 2.R(x)d4#)

Orthogonal setup with white correction and changed mates

Jacques Rotenberg
4 Pr Thèmes-64 1978
Ka6 Rb5 h5 Bd2 Sc4 e6 Pf5 g2 (Q2)a4 e8 - Ke4 Rd4 e5 Bd6 Pd3 d7 (10+6)#21.Rd5! [2.Rxd4#]
1...Rdxd5 2.Sc5#
1...Rexd5 2.Sxd6#
1...Kxd5 2.Sb6#
1...Bc5 2.Rxe5#

The pseudo-Plachutta is in fact square-blocks by the rooks that determine which -battery works.

Jacques Rotenberg
Phénix 1992
Kf2 Rg3 Sf8 h6 Pe7 (Q2)d8 h2 - Kh8 Rg8 h7 Bf7 (7+4)#21.Rg7! [2.Rxh7#]
1...Rhxg7 2.Sg6#
1...Rgxg7 2.Sxf7#
1...Kxg7 2.Sf5#
1...Bg6 2.Rxg8#

If it can be done more economically, why not?!

WinChloe includes one more fairy example by Jérôme Auclair, published in Phénix in 1998, but I don't know how I can draw the siamese pieces! :)
 
   
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(5) Posted by Hauke Reddmann [Monday, Mar 26, 2007 09:57]

THX for the examples. I hope I find the Brunner (Kraemer? Zepler)
problem so I can see what a Neudeutscher says on the matter.

The last two problems are especially interesting. Is it the same
theme, in spite of the double checks? I would say yes, since
RxS would parry if the other R on g7 would be permeable :-)

Hauke
 
 
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MatPlus.Net Forum General Plachutta in 2#