#2-94
#3-94
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#2-95
#3-95
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Mat Plus #2-96
#3-96
#n-96
h#-96
s#-96
#2-97
#3-97
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#2-98/99
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Mat Plus Informal Tourney: Moremovers 1995
Judge: Miodrag Radomirović

There were 12 problems by 9 authors from 5 countries (USA, Russia, France, Italy and Yugoslavia) published during 1995. in Mat Plus, issues 5 through 9. Despite relatively small number of entries, the quality was good, and order was decided by small details, especially when prizewinners are in question. Unfortunately, problem No.76 (#48) had to be eliminated due to an anticipation. Here is the result:


Milovan Belić
1.Pr Mat Plus 1995
16S4Q5k24S9K






#4 4+1
1st Prize: No.72 by Milovan Belic (Yugoslavia).
Surprising, perfect key (with given material the least one expects from White are withdrawals on first and second move), two wonderful model mates in main line, perfect construction without mutual touching in any stage of the play (Platonian problem) are the qualities that granted the first prize to this achievement. 1.Sc1! Kc4 2.Sc7! Kb4 3.Qd4+ Ka5/Ka3 4.Sb3/Sb5#, (2... Kc5 3.Sa2 Kc4 4.Qc3#); 1... Ke4 2.Kf2 Kd5 3.Ke3 Kc4 4.Qc6#.

Jakov Vladimirov
2.Pr Mat Plus 1995
6B4p5b1P1Rp2b2B1Kp4kpp5p1P2P1P2P3R3Q






#4 11+9
2nd Prize: No.135 by Jakov Vladimirov (Russia).
Openings of the white line (d1d5) in two corresponding variations, combined with successive white sacrifices of the White Pawn and Rook in the Bristol manner. Slightly inferior threat and by-variations suggest the constructional difficulties the author was faced to in realisation of the idea. 1.Qd1! ~ 2.Qb3 ed2 3.Rf4+ Ke5: 4.Qd5#; 1... Ke5: 2.d4+! Bd4: 3.Rc5+! Bc5: 4.Qd5# (3... Ke4 4.Rf4:); 1... Bd8 2.d3+! Bd3: 3.Rc4+! Bc4 4.Qd4# (3... Ke5 4.gf4, 2... Ke5: 3.Rc5+); (1... Bd3,Bc4 2.Qa4+, Rc4:+, etc.).

Alessandro Cuppini
1.HM Mat Plus 1995
3Q1b1KB1pR1pp3Pq2b4Prs6kP1P1B2P1p5P4s3S






#4 12+11
1st Hon. Mention: No.136 by Alessandro Cuppini (Italy).
Excellent problem by its contents. Realization of the complete cycle ABC-BCA-CAB is rare and hardly reachable goal. What spoils the impression, and the reason the problem was not placed higher, are the forced variations and, in essence, mechanical play. 1.Qg5! ~ 2.Sg3:+[A] Sg3: 3.Qe5:[B] Qe5: 4.Bc2[C]#; 1... Sd4 2.Qe5:[B]+ Qe5: 3.Bc2+[C] Sc2: 4.Sg3:[A]; 1... Qc5 2.Bc2+[C] Qc2: 3.Sg3:[A] Sg3: 4.Qe5:[B].

Aleksander Kuzovkov
2.HM Mat Plus 1995
Q7p2Sppr4psBpP1p1S7pk1P1PP2P5P1B1p7Kb






#4 12+12
2nd Hon. Mention: No.137 by Aleksander Kuzovkov (Russia).
If only the freshness of the solution decides the order, this problem would have been placed at very top in this award. A deep, classic style idea, with fourfold openings of d3d8 line by both sides, with sacrifices of the White Queen and both White Knights. The result are two complex variations with surprising mates, which make the strong impressions especially for solvers. 1.Qd8! ~ 2.Qe7:! 3.Qd6:(Bd4:); 1... Sg5 2.Sc5+ dc5 3.Sc3+ dc3(Ke3:) 4.Qd3(Bg5:)#; 1... Sd8: 2.Bd4! Kd5: 3.Bf3+ Ke6 4.Sf8#.

Yves Cheylan
1.Com Mat Plus 1995
16S10p8P1p7K6P1B7k






#4v 5+3
1st Com.: No.132 by Yves Cheylan (France).
An instructional and interesting problem. If you ever had a dilema whether to provide the opposite side with an en passant possibility, or to offer him a Pawn by a single step, this example gives a clear and elegant clue. 1.Sb4? de4!; 1.Sc5! d4 2.f3! 3.Sd3 4.Sf2# (2.f4? d3! 3.Sd3:? =), 1... de4 2.f4! e3 3.Sd3(Se4) (2.f3? e3!).

Vladan Vučković
2.Com Mat Plus 1995
4k2r2B2p4P2K1p7P2p3P6R






#4vv 6+5
2.Com: No.133 by Vladan Vuckovic (Yugoslavia).
Similar idea to the previous one, only the question here is to let or not to let the oponent to castle. Problem in spirit of Lepushutz theme, with aim to spoil the black castle: the exposure to the chack with switchback, but now without the castling possibility. Beautiful and not easy for realization, though the idea is not new. 1.Ra3? 0-0!; 1.Re3+? Kf8 2.Ra3 Kg8! 3.Ra8+ Kh7!; 1.Kg7! Rh7+ 2.Kf6! Kf8(Rh8) 3.Ra3 Kg8 4.Ra8#, 2... c3,Rg7 3.Rd3,Kg7: ~ 4.Rd8,Re3#; 1... Rg8+ 2.Kg8: Ke7 3.Re3+ Kf6 4.Bd8!#.

Edgar Holladay
Spec.Com Mat Plus 1995
12Q16k16B16K






#4 b) e1=a1
c) WBg3–›f3
d) WBg3–›f2
e) BKf5–›d1
3+1
Spec.Com.: No.73 by Edgar Holladay (USA).
The special commendation is granted to this problem for inovative attempts to discover the ideas which extend the composing field. In total there are 22 mates in this quintuple, 18 of which are echo models.

a) 1.Kg2 ~ 2.Kf3 Kg6 3.Bf4 Kf5 4.Qf7*#,1... Kg6 2.Qf8 Kh5 3.Qf6 Kg4 4.Qg6*# (2... Kh7 3.Qf7+ Kh6 3.Bf4#)

b) (all men left 4 squares) 1.Kd2? Kc4 2.Qa5 Kb3 3.Qb4+ Ka2 4.Qb2#, 1... Kc6!; 1.Qc7! Ka6 2.Kc2 Kb5 3.Qd6 Kc4 4.Qc6*# [2.Qd7? Kb6 3.Qc8 Ka7(Kb5!) 4.Bd4#; 2.Bd4? Kb5 3.Qc5+ Ka6(Ka4!) 4.Qb6#; 2.Ba5? Kb5 3.Qc3 Ka4(Ka6!) 4.Qb4#; 2.Qa5+? Kb7 3.Be5 Kc8(Kc6!) 4.Qc7#]

c) 1.Qd6? Kg5 2.Qf8 Kg6 3.Kg2 Kh7 4.Be4#, 3... Kc6!; 1.Bh5? Kf4 2.Qe6 Kg5 3.Qf7/Qg6 Kh6(Kh4!)/Kh4(Kh6!) 4.Qg6/Qg4#; 1.Kg2 Kf4 3.Qe6 Kg5 4.Kf2 Kf4 4.Qf6*# [2.Be4? Kg4(Ke3!) 3.Qf6 Kh5 4.Bf3#]

d) 1.Be3 Kg6 2.Qf8 Kh5 3.Qf5+ Kh4 4.Bf2# 3.Qg7? ~ 4.Qg5# 3... Kh4!], 2... Kh7 3.Qf7+ [3.Bh6? ~ 4.Qg7# 3... Kg6!]

e) 1.Qe3? Kc2 2.Bd6 Kd1 3.Qd3+ Kc1 4.Ba3#, 2... Kb1 3.Qb3+ Kc1 4.Bf4#, 2... Kb2!; 1.Bf4 Kc2 2.Qa3 Kd1 3.Qd3+ Kc1 4.Bg3# [3.Qb2? ~ 4.Qd2# 3... Ke1!] 2... Kb1 3.Qb3+ [3.Bc1? ~ 4.Qb2# 3... Kc2!].

Beograd, 27.06.2006
Miodrag Radomirović


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